x^2+x-6/(x+3)(x-2)=1

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Solution for x^2+x-6/(x+3)(x-2)=1 equation: 



x^2+x-6/(x+3)(x-2)=1

We move all terms to the left:

x^2+x-6/(x+3)(x-2)-(1)=0



Domain of the equation: (x+3)(x-2)!=0

We move all terms containing x to the left, all other terms to the right

x+3)(x!=2

x∈R



We multiply parentheses ..

x^2-6/(+x^2-2x+3x-6)+x-1=0

We multiply all the terms by the denominator


x^2*(+x^2-2x+3x-6)+x*(+x^2-2x+3x-6)-1*(+x^2-2x+3x-6)-6=0

We multiply parentheses

x^2*(+x^2-2x+3x-6)+x^3-2x^2+3x^2-1*(+x^2-2x+3x-6)-6x-6=0

We do not support expression: x^3

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